152. 乘积最大子数组

6

class Solution:
    def maxProduct(self, nums: List[int]) -> int:
        maxf = minf = nums[0]
        res, n = nums[0], len(nums)
        for i in range(1, n):
            p, q = maxf, minf
            maxf = max(nums[i], p * nums[i], q * nums[i])
            minf = min(nums[i], p * nums[i], q * nums[i])
            res = max(res, maxf)
        return res

class Solution {
    public int maxProduct(int[] nums) {
        int maxf = nums[0], minf = nums[0];
        int res = nums[0], n = nums.length;
        for (int i = 1; i < n; ++i) {
            int p = maxf, q = minf;
            maxf = Math.max(nums[i], Math.max(p * nums[i], q * nums[i]));
            minf = Math.min(nums[i], Math.min(p * nums[i], q * nums[i]));
            res = Math.max(res, maxf);
        }
        return res;
    }
}