1 Star 0 Fork 332

大宇 / leetcode

forked from doocs / leetcode 
加入 Gitee
与超过 1200万 开发者一起发现、参与优秀开源项目,私有仓库也完全免费 :)
免费加入
克隆/下载
README_EN.md 2.51 KB
一键复制 编辑 原始数据 按行查看 历史
ylb 提交于 2021-04-22 11:34 . feat: use relative path

1040. Moving Stones Until Consecutive II

中文文档

Description

On an infinite number line, the position of the i-th stone is given by stones[i].  Call a stone an endpoint stone if it has the smallest or largest position.

Each turn, you pick up an endpoint stone and move it to an unoccupied position so that it is no longer an endpoint stone.

In particular, if the stones are at say, stones = [1,2,5], you cannot move the endpoint stone at position 5, since moving it to any position (such as 0, or 3) will still keep that stone as an endpoint stone.

The game ends when you cannot make any more moves, ie. the stones are in consecutive positions.

When the game ends, what is the minimum and maximum number of moves that you could have made?  Return the answer as an length 2 array: answer = [minimum_moves, maximum_moves]

 

Example 1:


Input: [7,4,9]

Output: [1,2]

Explanation: 

We can move 4 -> 8 for one move to finish the game.

Or, we can move 9 -> 5, 4 -> 6 for two moves to finish the game.

Example 2:


Input: [6,5,4,3,10]

Output: [2,3]

We can move 3 -> 8 then 10 -> 7 to finish the game.

Or, we can move 3 -> 7, 4 -> 8, 5 -> 9 to finish the game.

Notice we cannot move 10 -> 2 to finish the game, because that would be an illegal move.

Example 3:


Input: [100,101,104,102,103]

Output: [0,0]

 

Note:

  1. 3 <= stones.length <= 10^4
  2. 1 <= stones[i] <= 10^9
  3. stones[i] have distinct values.
 

Solutions

Python3

Java

...

马建仓 AI 助手
尝试更多
代码解读
代码找茬
代码优化
Java
1
https://gitee.com/fdayu/leetcode.git
git@gitee.com:fdayu/leetcode.git
fdayu
leetcode
leetcode
main

搜索帮助

344bd9b3 5694891 D2dac590 5694891