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yanglbme 提交于 2020-10-20 11:19 . docs: prettify code

04.06. Successor

中文文档

Description

Write an algorithm to find the "next" node (i.e., in-order successor) of a given node in a binary search tree.

Return null if there's no "next" node for the given node.

Example 1:

[2,1,3], p = 1



  2

 / \

1   3

Example 2:

[5,3,6,2,4,null,null,1], p = 6



      5

     / \

    3   6

   / \

  2   4

 /   

1

Solutions

Python3

Java

...

Java
1
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