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Design a method to find the frequency of occurrences of any given word in a book. What if we were running this algorithm multiple times?
You should implement following methods:
WordsFrequency(book) constructor, parameter is a array of strings, representing the book.get(word) get the frequency of word in the book. Example:
WordsFrequency wordsFrequency = new WordsFrequency({"i", "have", "an", "apple", "he", "have", "a", "pen"});
wordsFrequency.get("you"); //returns 0，"you" is not in the book
wordsFrequency.get("have"); //returns 2，"have" occurs twice in the book
wordsFrequency.get("an"); //returns 1
wordsFrequency.get("apple"); //returns 1
wordsFrequency.get("pen"); //returns 1
Note:
There are only lowercase letters in book[i].1 <= book.length <= 1000001 <= book[i].length <= 10get function will not be called more than 100000 times.class WordsFrequency:
def __init__(self, book: List[str]):
self.counter = Counter(book)
def get(self, word: str) -> int:
return self.counter[word]
# Your WordsFrequency object will be instantiated and called as such:
# obj = WordsFrequency(book)
# param_1 = obj.get(word)
class WordsFrequency {
private Map<String, Integer> counter = new HashMap<>();
public WordsFrequency(String[] book) {
for (String word : book) {
counter.put(word, counter.getOrDefault(word, 0) + 1);
}
}
public int get(String word) {
return counter.containsKey(word) ? counter.get(word) : 0;
}
}
/**
* Your WordsFrequency object will be instantiated and called as such:
* WordsFrequency obj = new WordsFrequency(book);
* int param_1 = obj.get(word);
*/
/**
* @param {string[]} book
*/
var WordsFrequency = function (book) {
this.counter = {};
for (const word of book) {
this.counter[word] = (this.counter[word] || 0) + 1;
}
};
/**
* @param {string} word
* @return {number}
*/
WordsFrequency.prototype.get = function (word) {
return this.counter[word] || 0;
};
/**
* Your WordsFrequency object will be instantiated and called as such:
* var obj = new WordsFrequency(book)
* var param_1 = obj.get(word)
*/
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