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Given the root
of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:
Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Example 3:
Input: root = [] Output: 0
Example 4:
Input: root = [0] Output: 1
Constraints:
[0, 104]
.-100 <= Node.val <= 100
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if root is None:
return 0
l = self.maxDepth(root.left)
r = self.maxDepth(root.right)
return 1 + max(l, r)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int maxDepth(TreeNode root) {
if (root == null) return 0;
int l = maxDepth(root.left);
int r = maxDepth(root.right);
return 1 + Math.max(l, r);
}
}
class Solution {
public:
int maxDepth(TreeNode* root) {
if (!root) return 0;
int l = maxDepth(root->left);
int r = maxDepth(root->right);
return max(l, r) + 1;
}
};
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