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对链表进行插入排序。
插入排序的动画演示如上。从第一个元素开始,该链表可以被认为已经部分排序(用黑色表示)。
每次迭代时,从输入数据中移除一个元素(用红色表示),并原地将其插入到已排好序的链表中。
插入排序算法:
示例 1:
输入: 4->2->1->3 输出: 1->2->3->4
示例 2:
输入: -1->5->3->4->0 输出: -1->0->3->4->5
遍历链表,每次将遍历到的结点 cur 与前一个结点 pre 进行值比较:
依次遍历,直至 cur 指向空,遍历结束。
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def insertionSortList(self, head: ListNode) -> ListNode:
if head is None or head.next is None:
return head
dummy = ListNode(head.val, head)
pre, cur = dummy, head
while cur:
if pre.val <= cur.val:
pre, cur = cur, cur.next
continue
p = dummy
while p.next.val <= cur.val:
p = p.next
t = cur.next
cur.next = p.next
p.next = cur
pre.next = t
cur = t
return dummy.next
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public ListNode insertionSortList(ListNode head) {
if (head == null || head.next == null) {
return head;
}
ListNode dummy = new ListNode(head.val, head);
ListNode pre = dummy, cur = head;
while (cur != null) {
if (pre.val <= cur.val) {
pre = cur;
cur = cur.next;
continue;
}
ListNode p = dummy;
while (p.next.val <= cur.val) {
p = p.next;
}
ListNode t = cur.next;
cur.next = p.next;
p.next = cur;
pre.next = t;
cur = t;
}
return dummy.next;
}
}
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
var insertionSortList = function(head) {
if (head == null || head.next == null) return head;
let dummy = new ListNode(head.val, head);
let prev = dummy, cur = head;
while (cur != null) {
if (prev.val <= cur.val) {
prev = cur;
cur = cur.next;
continue;
}
let p = dummy;
while (p.next.val <= cur.val) {
p = p.next;
}
let t = cur.next;
cur.next = p.next;
p.next = cur;
prev.next = t;
cur = t;
}
return dummy.next;
};
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