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Given an array, rotate the array to the right by k
steps, where k
is non-negative.
Example 1:
Input: nums = [1,2,3,4,5,6,7], k = 3 Output: [5,6,7,1,2,3,4] Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1,2,3,4,5] rotate 3 steps to the right: [5,6,7,1,2,3,4]
Example 2:
Input: nums = [-1,-100,3,99], k = 2 Output: [3,99,-1,-100] Explanation: rotate 1 steps to the right: [99,-1,-100,3] rotate 2 steps to the right: [3,99,-1,-100]
Constraints:
1 <= nums.length <= 105
-231 <= nums[i] <= 231 - 1
0 <= k <= 105
Follow up:
O(1)
extra space?class Solution:
def rotate(self, nums: List[int], k: int) -> None:
"""
Do not return anything, modify nums in-place instead.
"""
n = len(nums)
k %= n
if n < 2 or k == 0:
return
nums[:] = nums[::-1]
nums[:k] = nums[:k][::-1]
nums[k:] = nums[k:][::-1]
class Solution {
public void rotate(int[] nums, int k) {
if (nums == null) {
return;
}
int n = nums.length;
k %= n;
if (n < 2 || k == 0) {
return;
}
rotate(nums, 0, n - 1);
rotate(nums, 0, k - 1);
rotate(nums, k, n - 1);
}
private void rotate(int[] nums, int i, int j) {
while (i < j) {
int t = nums[i];
nums[i] = nums[j];
nums[j] = t;
++i;
--j;
}
}
}
/**
* @param {number[]} nums
* @param {number} k
* @return {void} Do not return anything, modify nums in-place instead.
*/
var rotate = function (nums, k) {
k %= nums.length;
nums.splice(0, 0, ...nums.splice(-k, k))
};
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