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Given the root
of a binary tree, invert the tree, and return its root.
Example 1:
Input: root = [4,2,7,1,3,6,9] Output: [4,7,2,9,6,3,1]
Example 2:
Input: root = [2,1,3] Output: [2,3,1]
Example 3:
Input: root = [] Output: []
Constraints:
[0, 100]
.-100 <= Node.val <= 100
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def invertTree(self, root: TreeNode) -> TreeNode:
if root is None:
return None
root.left, root.right = root.right, root.left
self.invertTree(root.left)
self.invertTree(root.right)
return root
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode invertTree(TreeNode root) {
if (root == null) return null;
TreeNode t = root.left;
root.left = root.right;
root.right = t;
invertTree(root.left);
invertTree(root.right);
return root;
}
}
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {TreeNode}
*/
var invertTree = function (root) {
if (!root) return null;
[root.left, root.right] = [root.right, root.left];
invertTree(root.left);
invertTree(root.right);
return root;
};
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func invertTree(root *TreeNode) *TreeNode {
if (root == nil) {
return nil
}
root.Left, root.Right = root.Right, root.Left
invertTree(root.Left)
invertTree(root.Right)
return root
}
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