代码拉取完成,页面将自动刷新
有时候我们只是想备份数组,但是只是简单让它赋给一个变量,改变其中一个,另外一个就紧跟着改变,但很多时候这不是我们想要的。
var obj = {
name:'wsscat',
age:0
}
var obj2 = obj;
obj2['c'] = 5;
console.log(obj);//Object {name: "wsscat", age: 0, c: 5}
console.log(obj2);//Object {name: "wsscat", age: 0, c: 5}
解决上面的办法有4种:
var arr = ['wsscat', 'autumns', 'winds'];
var arrCopy = arr.slice(0);
arrCopy[0] = 'tacssw'
console.log(arr)//['wsscat', 'autumns', 'winds']
console.log(arrCopy)//['tacssw', 'autumns', 'winds']
var arr = ['wsscat', 'autumns', 'winds'];
var arrCopy = arr.concat();
arrCopy[0] = 'tacssw'
console.log(arr)//['wsscat', 'autumns', 'winds']
console.log(arrCopy)//['tacssw', 'autumns', 'winds']
var obj = {
name:'wsscat',
age:0
}
var obj2 = new Object();
obj2.name = obj.name;
obj2.age = obj.age
obj.name = 'autumns';
console.log(obj);//Object {name: "autumns", age: 0}
console.log(obj2);//Object {name: "wsscat", age: 0}
var obj = {
name: 'wsscat',
age: 0
}
var deepCopy = function(source) {
var result = {};
for(var key in source) {
if(typeof source[key] === 'object') {
result[key] = deepCopy(source[key])
} else {
result[key] = source[key]
}
}
return result;
}
var obj3 = deepCopy(obj)
obj.name = 'autumns';
console.log(obj);//Object {name: "autumns", age: 0}
console.log(obj3);//Object {name: "wsscat", age: 0}
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