1496. 判断路径是否相交

class Solution:
    def isPathCrossing(self, path: str) -> bool:
        i = j = 0
        vis = {(0, 0)}
        for c in path:
            match c:
                case 'N':
                    i -= 1
                case 'S':
                    i += 1
                case 'E':
                    j += 1
                case 'W':
                    j -= 1
            if (i, j) in vis:
                return True
            vis.add((i, j))
        return False

class Solution {
    public boolean isPathCrossing(String path) {
        int i = 0, j = 0;
        Set<Integer> vis = new HashSet<>();
        vis.add(0);
        for (int k = 0, n = path.length(); k < n; ++k) {
            switch (path.charAt(k)) {
                case 'N' -> --i;
                case 'S' -> ++i;
                case 'E' -> ++j;
                case 'W' -> --j;
            }
            int t = i * 20000 + j;
            if (!vis.add(t)) {
                return true;
            }
        }
        return false;
    }
}

class Solution {
public:
    bool isPathCrossing(string path) {
        int i = 0, j = 0;
        unordered_set<int> s{{0}};
        for (char& c : path) {
            if (c == 'N') {
                --i;
            } else if (c == 'S') {
                ++i;
            } else if (c == 'E') {
                ++j;
            } else {
                --j;
            }
            int t = i * 20000 + j;
            if (s.count(t)) {
                return true;
            }
            s.insert(t);
        }
        return false;
    }
};

func isPathCrossing(path string) bool {
	i, j := 0, 0
	vis := map[int]bool{0: true}
	for _, c := range path {
		switch c {
		case 'N':
			i--
		case 'S':
			i++
		case 'E':
			j++
		case 'W':
			j--
		}
		if vis[i*20000+j] {
			return true
		}
		vis[i*20000+j] = true
	}
	return false
}

function isPathCrossing(path: string): boolean {
    let [i, j] = [0, 0];
    const vis: Set<number> = new Set();
    vis.add(0);
    for (const c of path) {
        if (c === 'N') {
            --i;
        } else if (c === 'S') {
            ++i;
        } else if (c === 'E') {
            ++j;
        } else if (c === 'W') {
            --j;
        }
        const t = i * 20000 + j;
        if (vis.has(t)) {
            return true;
        }
        vis.add(t);
    }
    return false;
}