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README
Apache-2.0

您发现了我,让您快速便捷使用Hibernate CRUD的 DAO 小工具


1. 方法API

基础方法

方法 返回 参数 说明
getSession() org.hibernate.session 获取session
save(Object) ID 泛型指定类型的主键 POJO实体 保存记录
update(Object) boolean 成功与否 POJO实体 更新记录
merge(Object) boolean 成功与否 POJO实体 合并记录
delete(Object) boolean 成功与否 POJO实体 删除记录
deleteById(ID) boolean 成功与否 ID主键 根据ID删除记录

HQL相关查询方法

方法 返回 参数 说明
find(String, Object...) 用户指定泛型E的List hql, params 列表查询
findFirst(String, Object...) 用户指定泛型E hql, params 首条查询
findPage(String, int, int, Object...) 用户指定泛型E的List hql, start, pageSize, params 分页查询

SQL相关查询方法,在返回值转换上会比hql方法多一个参数class

方法 返回 参数 说明
findSQL(String, Object...) 用户指定泛型E的List sql, params 列表查询,sql查询方式不指定class只能返回Map
findSQL(Class, String, Object...) 用户指定泛型E的List pojoClass, sql, params 列表查询并转换为指定类型
findFirstSQL(String, Object...) 用户指定泛型E sql, params 首条查询
findFirstSQL(Class, String, Object...) 用户指定泛型E objClass, sql, params 首条查询并转换为指定类型
findPageSQL(String, int, int, Object...) 用户指定泛型E的List sql, start, pageSize, params 分页查询
findPageSQL(Class, String, int, int, Object...) 用户指定泛型E的List pojoClass, sql, start, pageSize, params 分页查询并转换为指定类型
executeSQL(String, Object...) 受影响条数 sql, params 执行更新语句

2. 您需要一个Pojo实体


@Entity  
@Table(name="user")
public class User {
	
	@Id  
	@Column
	@GeneratedValue(strategy=GenerationType.AUTO)
	private int id;
	@Column
	private String nickname;
	@Column
	private String account;
	@Column
	private String password;
	@Column
	private String roles;
    
    // getter setter
    	
}

3. 您需要在hibernate.cfg.xml里添上映射


<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
        "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
        "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>
	
	<session-factory>
        <!-- 链接配置 -->
        ......
        
        <!-- 映射配置 -->
        <!-- xml使用resource -->
        <!-- 注解使用class -->
        <mapping class="me.cjd.pojo.User"/>
	
    </session-factory>

</hibernate-configuration>

4. 您还需要一个DAO

单独使用方法,请继承 DefaultSessionDAO,且必须使用ProxyKit进行事务托管

public class UserDAO extends DefaultSessionDAO<User, Integer> {
	
	public static final UserDAO me = new UserDAO();
	
}
// 必须要托管然后通过service调用噢,不然无法正常运行
private UserService service = ProxyKit.transaction(new UserService());

集成 Spring 方法,请继承 SpringSessionDAO 并在 Spring 配置里向 dao 注入 session

public class UserDAO extends SpringSessionDAO<User, Integer> {
	
	public static final UserDAO me = new UserDAO();
	
}

5. 使用范例

基础方法

@Test
public void save(){
    User user = new User();
    user.setNickname("测试");
    user.setAccount("test");
    Integer id = UserDAO.me.save(user);
    System.out.println("保存ID是 = " + id);
    assertNotNull(id);
}

@Test
public void update(){
	User user = UserDAO.me.getById(1);
	assertNotNull(user);
	String newPassword = Integer.toString(2);
	user.setPassword(newPassword);
	int count = UserDAO.me.update(user);
	assertEquals(count, 1);
	assertEquals(user.getPassword(), newPassword);
}

@Test
public void delete(){
	User user = UserDAO.me.getById(1);
	boolean result = UserDAO.me.delete(user);
	assertEquals(result, true);
}

@Test
public void deleteById(){
	boolean result = UserDAO.me.deleteById(1);
	assertEquals(result, true);
}

HQL相关


@Test
public void findHql(){
	List<User> list = UserDAO.me.find("from User");
	assertNotNull(list);
}

@Test
public void findHqlPage(){
	List<User> page1 = UserDAO.me.findPage("from User", 0, 5);
	assertNotNull(page1);
	System.out.println(page1.get(0).getNickname());
}

@Test
public void findFirst(){
    // 返回类型任意指定
	String nickname = UserDAO.me.findFirst("select nickname from User");
	assertNotNull(nickname);
	System.out.println(nickname);
	
	User user = UserDAO.me.findFirst("from User where id = 1 ");
	assertNotNull(user);
}

SQL相关


@Test
public void findSql(){
    // 返回pojo需指定class
	List<User> list = UserDAO.me.findSQL(User.class, "select * from user");
	assertNotNull(list);
	System.out.println(list.get(0).getNickname());
	
	// 默认则返回map
	List<Map<String, Object>> list2  = UserDAO.me.findSQL("select * from user");
	assertNotNull(list2);
	System.out.println(list2.get(0).get("nickname"));
}

@Test
public void findPageSql(){
    // 返回pojo需指定class, 默认则返回map
	List<User> page1 = UserDAO.me.findPageSQL(User.class, "select * from user", 0, 5);
	assertNotNull(page1);
	assertEquals(page1.size(), 5);
	System.out.println(page1.get(0).getNickname());
}

@Test
public void findFirstSql(){
    // 不指定class只可返回基础类型 string, int, long 之类的
	String nickname = UserDAO.me.findFirstSQL("select nickname from user");
	assertNotNull(nickname);
	System.out.println(nickname);
	
	// 指定类型可返回实体
	User user = UserDAO.me.findFirstSQL(User.class, "select * from user");
	assertNotNull(user);
	System.out.println(user.getNickname());
}

@Test
public void sqlExc(){
    // sql 执行更新语句
    int count = UserDAO.me.executeSQL("update user set password = ? where id = ? ", 1, "2");
    assertEquals(count, 1);
}

未完待续 感谢您花费时间阅读这份说明稿。

作者 cjd
2016 年 11月15日

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Hibernate工具,事务代理托管,CRUD便捷方法封装 ~ 展开 收起
Java
Apache-2.0
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