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You are given a 2D array of integers envelopes
where envelopes[i] = [wi, hi]
represents the width and the height of an envelope.
One envelope can fit into another if and only if both the width and height of one envelope are greater than the other envelope's width and height.
Return the maximum number of envelopes you can Russian doll (i.e., put one inside the other).
Note: You cannot rotate an envelope.
Example 1:
3
Example 2:
Input: envelopes = [[1,1],[1,1],[1,1]] Output: 1
Constraints:
1 <= envelopes.length <= 5000
envelopes[i].length == 2
1 <= wi, hi <= 104
class Solution:
def maxEnvelopes(self, envelopes: List[List[int]]) -> int:
if not envelopes:
return 0
envelopes.sort(key=lambda x: (x[0], -x[1]))
nums = [x[1] for x in envelopes]
n = len(nums)
dp = [1] * n
res = 1
for i in range(1, n):
for j in range(i):
if nums[j] < nums[i]:
dp[i] = max(dp[i], dp[j] + 1)
res = max(res, dp[i])
return res
class Solution {
public int maxEnvelopes(int[][] envelopes) {
int n;
if (envelopes == null || (n = envelopes.length) == 0) return 0;
Arrays.sort(envelopes, (a, b) -> {
return a[0] == b[0] ? b[1] - a[1] : a[0] - b[0];
});
int[] dp = new int[n];
Arrays.fill(dp, 1);
int res = 1;
for (int i = 1; i < n; ++i) {
for (int j = 0; j < i; ++j) {
if (envelopes[j][1] < envelopes[i][1]) {
dp[i] = Math.max(dp[i], dp[j] + 1);
}
}
res = Math.max(res, dp[i]);
}
return res;
}
}
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